Free Pearson Edexcel International A-level Mathematics · FP2

Maclaurin and Taylor series

What you’ll learn

  • Build expansions from successive derivatives.
  • Use series for local approximations and equations.

Understand the idea

A Taylor expansion describes a function near a chosen point through its derivatives there. A Maclaurin expansion is the special case centred at zero. The factorial in each denominator compensates for repeated differentiation.

For a composite expression, substitute into a known expansion or multiply and collect terms only up to the requested degree. A truncated series is a local approximation: state the order retained and respect the convergence interval of any infinite expansion. Differential equations can also generate successive derivatives at an initial point.

Key formulae

f(a+h)=f(a)+hf′(a)+h22!f′′(a)+⋯f(a+h)=f(a)+hf'(a)+\frac{h^2}{2!}f''(a)+\cdots

ex=1+x+x22!+x33!+⋯e^x=1+x+\frac{x^2}{2!}+\frac{x^3}{3!}+\cdots

sin⁡x=x−x33!+⋯\sin x=x-\frac{x^3}{3!}+\cdots

ln⁡(1+x)=x−x22+x33−⋯(∣x∣<1)\ln(1+x)=x-\frac{x^2}{2}+\frac{x^3}{3}-\cdots\quad(|x|<1)

A Taylor polynomial matches locally but is not identical

Conditions. Compare eˣ with Maclaurin truncation 1+x+x²/2 on −1≤x≤1. The polynomial matches value and first two derivatives at zero.

x / dimensionless; Output / dimensionless.

At x=0 both equal 1; at x=1 the approximation gives 2.5 rather than e≈2.718. A larger interval can make omitted terms more important even though the complete exponential series converges everywhere.

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Worked example

Expand e2xe^{2x} through the term in x3x^3.

  1. Begin with eu=1+u+u2/2+u3/6+⋯e^u=1+u+u^2/2+u^3/6+\cdots.
  2. Substitute u=2xu=2x.
  3. Simplify each coefficient: 4/2=24/2=2 and 8/6=4/38/6=4/3.

Answer: e2x=1+2x+2x2+43x3+⋯e^{2x}=1+2x+2x^2+\frac43x^3+\cdots.

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