Free Pearson Edexcel International A-level Mathematics · FP2

Polar curves, tangents and areas

What you’ll learn

  • Convert between polar and Cartesian descriptions.
  • Calculate polar areas and locate horizontal or vertical tangents.

Understand the idea

Polar coordinates describe a point by its distance rr from the pole and angle θ\theta from the initial line. In this unit take r≥0r\ge0, so sketch only angle intervals where the radius is non-negative. Symmetry and values at key angles help reveal the curve.

A polar area is built from thin sectors, giving one half of the integral of r2r^2. Choose bounds that trace the intended region exactly once. For tangents, differentiate x=rcos⁡θx=r\cos\theta and y=rsin⁡θy=r\sin\theta; a horizontal tangent normally has dy/dθ=0dy/d\theta=0 with dx/dθ≠0dx/d\theta\ne0, and conversely for a vertical tangent.

Key formulae

x=rcos⁡θ,y=rsin⁡θx=r\cos\theta,\qquad y=r\sin\theta

A=12∫αβr2 dθA=\frac12\int_\alpha^\beta r^2\,d\theta

dydx=r′sin⁡θ+rcos⁡θr′cos⁡θ−rsin⁡θ\frac{dy}{dx}=\frac{r'\sin\theta+r\cos\theta}{r'\cos\theta-r\sin\theta}

Worked example

Find the area enclosed by r=4cos⁡θr=4\cos\theta, using −π/2≤θ≤π/2-\pi/2\le\theta\le\pi/2.

  1. The chosen interval keeps r≥0r\ge0 and traces the circle once.
  2. The area is 8∫−π/2π/2cos⁡2θ dθ8\int_{-\pi/2}^{\pi/2}\cos^2\theta\,d\theta.
  3. Use cos⁡2θ=(1+cos⁡2θ)/2\cos^2\theta=(1+\cos2\theta)/2; the integral is π/2\pi/2.

Answer: 4π4\pi square units.

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