Free Pearson Edexcel International A-level Mathematics · S2

Binomial and Poisson hypothesis tests

What you’ll learn

  • State hypotheses about a population parameter.
  • Calculate an appropriate tail probability or critical region.
  • Give a conclusion with its significance and context.

Understand the idea

The null hypothesis specifies a reference value of a population parameter; the alternative gives the change being investigated. Choose a one-sided or two-sided alternative before inspecting the result. Calculate probabilities using the null model, not an estimated parameter substituted from the very observation being tested.

A tail probability measures how unusual the observed result, or a more extreme one in the chosen direction, would be under the null. Reject the null when this probability is at most the chosen significance level. Alternatively, construct a critical region whose null probability does not exceed the allowed level. Discrete counts often make the actual significance smaller than the nominal value.

For a two-sided discrete test, a standard approach allocates at most half the significance to each tail, following any specified convention. A significant result is evidence against the null model, not certainty. A non-significant result means insufficient evidence of change; it does not prove the null hypothesis.

Key formulae

H0:p=p0,H1:p>p0H_0:p=p_0,\qquad H_1:p>p_0

PH0(X≥xobs)P_{H_0}(X\geq x_{\mathrm{obs}})

PH0(X∈C)≤αP_{H_0}(X\in C)\leq\alpha

actual significance=PH0(reject H0)\text{actual significance}=P_{H_0}(\text{reject }H_0)

Worked example

A fair-selection claim says success has probability 0.5. In 12 independent trials there are 10 successes. Test for an increased success probability at the 5% level.

  1. State H0:p=0.5H_0:p=0.5 and H1:p>0.5H_1:p>0.5. Under H0H_0, X∼B(12,0.5)X\sim B(12,0.5).
  2. The relevant upper tail is P(X≥10)P(X\geq10).
  3. P(X≥10)P(X\geq10) =((1210)+(1211)+(1212))/212=(\binom{12}{10}+\binom{12}{11}+\binom{12}{12})/2^{12} =79/4096=79/4096 =0.01929=0.01929.
  4. Since 0.01929<0.050.01929<0.05, reject H0H_0. There is evidence of an increased success probability.

Answer: Reject the null at 5%; the data provide evidence that the success probability exceeds 0.5.

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