Free Pearson Edexcel International A-level Mathematics · P3

Advanced identities and harmonic forms

What you’ll learn

  • Use reciprocal, compound-angle and double-angle identities.
  • Rewrite sine–cosine combinations in a single harmonic form.
  • Use inverse trigonometric principal ranges correctly.

Understand the idea

Secant, cosecant and cotangent are the reciprocals of cosine, sine and tangent where defined. Their asymptotes occur where the relevant denominator is zero. The principal ranges of arcsin⁡\arcsin, arccos⁡\arccos and arctan⁡\arctan select a single inverse value; an equation may still have additional solutions in its stated interval.

Compound-angle identities connect the trigonometric values of a sum or difference to those of its parts. Setting both angles equal gives sin⁡2x=2sin⁡xcos⁡x\sin2x=2\sin x\cos x and cos⁡2x\cos2x =cos⁡2x−sin⁡2x=\cos^2x-\sin^2x =1−2sin⁡2x=1-2\sin^2x =2cos⁡2x−1=2\cos^2x-1. For tangent, tan⁡(A+B)=(tan⁡A+tan⁡B)/(1−tan⁡Atan⁡B)\tan(A+B)=(\tan A+\tan B)/(1-\tan A\tan B) where defined. Choose the form that reduces the number of different functions in a calculation.

An expression acos⁡x+bsin⁡xa\cos x+b\sin x can be written as Rcos⁡(x−α)R\cos(x-\alpha) by matching coefficients. The amplitude R=a2+b2R=\sqrt{a^2+b^2} gives the maximum and minimum immediately. Determine the quadrant of α\alpha using the signs of both coefficients, not only a calculator's inverse tangent.

Key formulae

sec⁡2x=1+tan⁡2x,csc⁡2x=1+cot⁡2x\sec^2x=1+\tan^2x,\qquad \csc^2x=1+\cot^2x

sin⁡(A±B)=sin⁡Acos⁡B±cos⁡Asin⁡B\sin(A\pm B)=\sin A\cos B\pm\cos A\sin B

cos⁡(A±B)=cos⁡Acos⁡B∓sin⁡Asin⁡B\cos(A\pm B)=\cos A\cos B\mp\sin A\sin B

acos⁡x+bsin⁡x=Rcos⁡(x−α),Rcos⁡α=a, Rsin⁡α=ba\cos x+b\sin x=R\cos(x-\alpha),\quad R\cos\alpha=a,\ R\sin\alpha=b

A harmonic form combines two oscillations at one frequency

Conditions. Exact function 3 cos x + 4 sin x = 5 cos(x − α), where cos α = 3/5 and sin α = 4/5. Angles are in radians; sampled extrema are approximate.

Angle x / rad; Output / dimensionless.

The amplitude is √(3² + 4²) = 5, not 7. The peak is shifted to α ≈ 0.927 rad. At x = 0 the output is 3, showing that amplitude is not necessarily the initial height.

Open the interactive lesson to view plotted curves and coordinate tables.

Worked example

Write 3cos⁡x+4sin⁡x3\cos x+4\sin x as Rcos⁡(x−α)R\cos(x-\alpha), with R>0R>0 and 0<α<90∘0<\alpha<90^\circ, and state its maximum.

  1. Expand Rcos⁡(x−α)=Rcos⁡αcos⁡x+Rsin⁡αsin⁡xR\cos(x-\alpha)=R\cos\alpha\cos x+R\sin\alpha\sin x.
  2. Match coefficients: Rcos⁡α=3R\cos\alpha=3 and Rsin⁡α=4R\sin\alpha=4, giving R=5R=5.
  3. Both coefficients are positive, so α\alpha is in the first quadrant and α=tan⁡−1(4/3)\alpha=\tan^{-1}(4/3).

Answer: 5cos⁡(x−53.130…∘)5\cos(x-53.130\ldots^\circ); maximum 55.

Open the interactive lesson to try original questions and recall. Build a revision plan.