Free Pearson Edexcel International A-level Mathematics · FP1

Sums of powers and finite series

What you’ll learn

  • Use standard sums of integers, squares and cubes.
  • Rewrite polynomial summands and shifted ranges.

Understand the idea

Sigma notation tells you both the expression to add and the integer range. A polynomial in the summation variable can be split into standard sums using linearity; constants must be counted once for every term.

When a range begins after 11, subtract the unwanted initial sum from a sum beginning at 11. Expand a shifted expression such as (r+1)2(r+1)^2 before applying formulas, and check a proposed result with a small value of nn.

Key formulae

∑r=1nr=n(n+1)2\sum_{r=1}^n r=\frac{n(n+1)}2

∑r=1nr2=n(n+1)(2n+1)6\sum_{r=1}^n r^2=\frac{n(n+1)(2n+1)}6

∑r=1nr3=n2(n+1)24\sum_{r=1}^n r^3=\frac{n^2(n+1)^2}{4}

∑r=mnf(r)=∑r=1nf(r)−∑r=1m−1f(r)\sum_{r=m}^n f(r)=\sum_{r=1}^n f(r)-\sum_{r=1}^{m-1}f(r)

A finite sum of integers grows quadratically

Conditions. Integer points Sₙ =n(n+1)/2 for n=1,…,10. Connecting line segments guide the eye; sums are defined here only for integer term counts.

Integer n / count; Sum 1 through n / dimensionless.

S₄ =10 and S₁₀ =55. Adding the next integer gives Sₙ₊₁ −Sₙ =n+1, so equal increases in n do not add a constant amount to the sum.

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Worked example

Find a formula for ∑r=1nr(r+2)\sum_{r=1}^n r(r+2).

  1. Expand the summand to r2+2rr^2+2r.
  2. Use n(n+1)(2n+1)6+2n(n+1)2\frac{n(n+1)(2n+1)}6+2\frac{n(n+1)}2.
  3. Factor out n(n+1)/6n(n+1)/6 and combine 2n+1+62n+1+6.

Answer: n(n+1)(2n+7)6\frac{n(n+1)(2n+7)}6.

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