Free Pearson Edexcel International A-level Chemistry · Unit 4
Carboxylic acids, acyl derivatives and polyesters
What you’ll learn
- Predict reactions of carboxylic acids and acyl chlorides.
- Distinguish acidic and alkaline ester hydrolysis.
- Identify condensation-polymer linkages.
Understand the idea
Carboxylic acids are weak acids and can form hydrogen bonds, including dimers in suitable non-aqueous environments. Short-chain acids dissolve readily in water, while a longer hydrocarbon chain reduces water solubility. They react with bases and carbonates to form salts, and with alcohols in an acid-catalysed equilibrium to form esters. Reduction of a carboxylic acid gives a primary alcohol.
Acyl chlorides are reactive carboxylic-acid derivatives. Water gives a carboxylic acid, alcohols give esters, and ammonia or primary and secondary amines give amides; hydrogen chloride is produced and may be neutralised by additional base. Acidic ester hydrolysis is reversible and gives an acid plus an alcohol. Alkaline hydrolysis gives a carboxylate salt plus an alcohol and is driven forward by formation of the carboxylate.
Condensation polymerisation joins bifunctional molecules while removing small molecules. A diol and a dicarboxylic acid can form a polyester with repeated ester links; a hydroxycarboxylic acid can also polymerise because each molecule contains both required functional groups. Show the bonds continuing through the repeat-unit brackets and retain the carbonyl oxygen in every ester linkage.
Key formulae
Worked example
Predict the organic products when ethyl propanoate undergoes alkaline hydrolysis, and explain the naming.
- The propanoate portion contains the carbonyl carbon and comes from propanoic acid.
- Alkaline hydrolysis produces the propanoate ion rather than the free acid.
- The ethyl portion attached through oxygen becomes ethanol.
Answer: Propanoate ions and ethanol; the accompanying metal ion determines the carboxylate salt.
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