Free Pearson Edexcel International A-level Biology · Unit 3

Microscope calibration, cell drawings and plant tissues

What you’ll learn

  • Calibrate an eyepiece graticule and calculate actual size or magnification.
  • Distinguish a tissue plan from a cell drawing.
  • Identify plant transport tissues using supplied structural evidence.

Understand the idea

Core practicals 5 and 7 connect animal-cell observations with plant-cell and tissue observations. An eyepiece graticule has arbitrary divisions until it is calibrated against a stage micrometer at the selected objective. Recalibrate when the objective changes. Magnification compares image size with actual object size using the same length units; resolution describes the ability to distinguish close points, so increasing magnification alone does not necessarily reveal more detail.

A biological drawing should record the structures actually visible, with clear boundaries, accurate proportions and unambiguous label lines. A plan diagram shows the arrangement and relative sizes of tissues rather than individual cells. A detailed cell drawing instead shows the observable cellular features. Include an appropriate scale bar or stated magnification, and do not draw organelles simply because a textbook says they exist if the chosen microscope cannot resolve them.

In plant sections, identify tissues from a combination of position and structure. Xylem vessels commonly have large lumens and thick lignified walls; phloem includes sieve-tube elements and associated companion cells; sclerenchyma fibres have thick supporting walls. Their arrangement differs among roots, stems and leaves, so a generic pattern should not replace the section's actual evidence. Stains improve contrast, while thin, well-prepared sections reduce overlapping structures; preparation is supervised where blades or stains are used.

Key formulae

size per graticule division=known stage lengthmatching graticule divisions\mathrm{size\ per\ graticule\ division}=\frac{\mathrm{known\ stage\ length}}{\mathrm{matching\ graticule\ divisions}}

M=image sizeactual sizeM=\frac{\mathrm{image\ size}}{\mathrm{actual\ size}}

1 mm=1000 μm1\ \mathrm{mm}=1000\ \mu\mathrm{m}

Worked example

At one objective setting, 40 graticule divisions span 100 μm100\ \mu\mathrm{m}. A cell spans 18 divisions and its drawing is 36.0 mm36.0\ \mathrm{mm} long. Find the cell's actual length and the drawing magnification.

  1. One graticule division represents 100/40=2.5 μm100/40=2.5\ \mu\mathrm{m}.
  2. The cell length is 18×2.5=45 μm18\times2.5=45\ \mu\mathrm{m}.
  3. The drawing length is 36000 μm36000\ \mu\mathrm{m}, so magnification is 36000/45=80036000/45=800.

Answer: Actual length 45 μm45\ \mu\mathrm{m}; drawing magnification ×800\times800.

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